The proportion of field mice weighing more than 33 grams in the distribution will be about 0.2275
- Mean, μ = 25 grams
- Standard deviation, σ = 4 grams
- Score, X = 33 grams
We need to calculate the P(Z > Zscore)
Recall :
Zscore = (X - μ) ÷ σ
For X > 33 :
Zscore = (33 - 25) ÷ 4 = 2
Therefore, the probability would be expressed as :
P(Z > 2) = 1 - P(Z < 2)
From the normal distribution table :
P(Z < 2) = 0.97725
Therefore,
P(Z > 2) = 1 - 0.97725 = 0.02275
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Answer:
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Answer:
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The correct answer is composite score.
The Composite score is the average of an individual's test scores in four different examinations, adjusted to the closest entire number. Parts short of what one-half are adjusted down; portions one-half or more are gathered together. Examinations may include subjects such as Mathematics, English, Reading and Science.