Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.
The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!
Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.
y>x-2 -6> -4-2 -6= -6
That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.
y>2x+2
-6>(2)(-4) +2
-6> -8 +2
-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.
If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.
Answer:
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Answer:
y = (-4/3)x + 6
Step-by-step explanation:
The Y-intercept of the graph is 6. You can find the slope by following rise over run, or the change in y divided by the change in x. From (0,6) to (3,2), there is a negative 4 change in y and positive 3 change in x.
Answer:
-25/36
Step-by-step explanation:
-5/6 x 5/6 = -25/36
There is no way to simplify it.
You just needed to multiply the deniminators and the numerators. And since you can't simplity -25/36, you have your answer.
Subtract 43 from both sides
-6p=-30
Divide both sides by -6
p=5
Final answer: p=5
