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Monica [59]
2 years ago
6

Which of the following is the solution to the equation

Mathematics
1 answer:
enot [183]2 years ago
5 0

Answer: you anwser is 5.5 i got this

Step-by-step explanation:

given

25^(z - 4) = 125

ln(25^(z - 4)) = ln (125)

(z-4)ln(25) = ln(125)

z = ln(125)/ln(25) + 4

z = 5.5

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Help!!!me please please
3241004551 [841]

Answer:

35y^4

Step-by-step explanation:

(−7)*y3*(−5)*y

35*y^4

6 0
3 years ago
Read 2 more answers
The balance on Matthew’s gift card is $228. His card was debited by $178 from purchasing several items. What is the remaining ba
Natasha_Volkova [10]

Answer:

50 dollars

Step-by-step explanation:

228-178=50

5 0
2 years ago
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even. what kind of proof did you
scoray [572]
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n

Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
6 0
3 years ago
Which of the following is the standard form of the equation 5x2 - 20x = 15?
Finger [1]

x= +7 or x=2-7 let me know if you need an explanation <3
5 0
2 years ago
A cutting tool fails due to flank wear while machining. It is observed that the tool life at a cutting speed of 160 m/min is 5 m
Ahat [919]

Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.

8 0
2 years ago
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