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1 year ago

Solve for x. Round your answer to the nearest tenth. 42 37 X= units

Mathematics

1 answer:

natita [175]1 year ago

6 0

Answer:

Step-by-step explanation:

That little square gives you a hint that it's an 90 degree angle/ acute angle First add 42 and 37 and you will get 79. Next subtract 79 from 90 and you will get 11. (5 or more, raise the score, for or less, let it rest.) 11 equals 10.

Numarical form:

47 + 37 = 79

90 - 79 = 11

11 = 10

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Factor to write an equivalent expression.(What is the Greatest Common Factor?). −9x+15y

KengaRu [80]

Answer:

GCF is 3

Step-by-step explanation:

Given the expression -9x + 15y

First, we need to find ther individual factors

-9x = -3 *3 * x

15y = 3 * 5 * y

Since 3 is common to both factors

−9x+15y = 3(-3x+5y)

Hence the GCF is 3

3 0

2 years ago

Use a calculator to find the trigonometric ratio to four decima place tan 23

Aneli [31]

Answer:

=0.4245 (4dp)

Step-by-step explanation:

tan(23)=0.4244748162

=0.4245 (4dp)

I hope this helps!

4 0

2 years ago

During a flu epidemic, 35% of the school's students have the flu. Of those with the flu, 90% have high

frutty [35]

Answer: 0.8015

Step-by-step explanation:

Let F= event that a person has flu

H= event that person has a high temperature.

As per given,

P(F) =0.35

Then P(F')= 1- 0.35= 0.65 [Total probability= 1]

P(H | F) = 0.90

P(H|F') = 0.12

By Bayes theorem, we have

$P(F|H)=\dfrac{P(F)\timesP(H|F)}{P(F)\timesP(H|F)+P(F')\timesP(H|F')}\\\\=\dfrac{0.35\times0.90}{0.35\times0.90+0.65\times0.12}\\\\=\dfrac{0.315}{0.315+0.078}\approx0.8015$

Required probability = 0.8015

8 0

2 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

2 years ago

How can I tell when figures are similar?

Anestetic [448]

Two figures that have the same shape are said to be similar. When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles below are similar, compare their corresponding sides.

4 0

2 years ago

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