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hoa [83]
2 years ago
14

If a coin is tossed 4 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn f

rom a standard deck of 52 cards without replacement, how many different outcomes are possible?
Mathematics
2 answers:
forsale [732]2 years ago
8 0

Answer there are 3 outcomes

Step-by-step explanation:

Ivanshal [37]2 years ago
6 0

Answer:

89,820,057,600.

Step-by-step explanation:

For the number of ways 5 cards can be taken from a standard 52 card deck, there are 52 choices for the first card. After the first card is chosen, there are 51 choices remaining for the second card. Following this pattern, you will the total number of ways the 5 cards can be chosen being 52 x 51 x 50 x 49 x 48 = 311,875,200. Or, you can also use the permutation of 52 cards taken 5 at a time which is 52!/(52 – 5)! = 311,875,200.

Hence, the total number of outcomes for all the above is 8 x 36 x 311,875,200 = 89,820,057,600.

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