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Dimas [21]
2 years ago
9

Can someone please help me

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
3 0

Okay, so I had to resort to the calculator since I couldn't figure out how to do it, anyway here.

(-0.08928571428) -this is the answer according to it id says take a few numbers and see what answer fits it the most but yeah, I didn't help much.

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1. Use Euler’s formula to find the missing number.
andriy [413]
V + f = a + 2
15 + f = 24 + 2

f = 26 - 15
f = 11 (11 faces)

height = 43 m
d = 14m
r = 7 m
A = π.r.g
g² = r²+h²
g² = 7²+43²
g² = 1898
g = \/1898
g ~ 43,56 m
A = π.r.g
A = π.7.43,56
A = 304,92 π
A = 304,92*3,14
A = 957,45 m² (área lateral)
3 0
2 years ago
Read 2 more answers
I need extra help -(-24/8)2 squared
weqwewe [10]
Well following order of operations you do:
(-24/8)^2 first and add the other negative to answer after
= -9
8 0
2 years ago
Combine like terms to simplify -1(2/7b + 9) -8
Rus_ich [418]

Simplify 2/7b to 2b/7

-1 × (2b/7 + 9) - 8

Simplify 1 × (2b/7 + 9) to (2b/7 + 9)

-(2b/7 + 9) - 8

Simplify brackets

-2b/7 - 9 - 8

Collect like terms

-2b/7 + (-9 - 8)

Simplify

<u>-2b/7 - 17</u>

8 0
3 years ago
Which of the rectangles below have an area of 18 cm²?
Elenna [48]

\textsf{Rectangle A}

\implies \mathsf {Area = 3 \times 6 = 18cm^{2}}

\implies \bf {Yes}

\textsf {Rectangle B}

\implies \mathsf {Area = 2 \times 9 = 18cm^{2}}

\implies \bf {Yes}

\textsf {Rectangle C}

\implies \mathsf {Area = 5 \times 4 = 20cm^{2}}

\textsf {Rectangle D}

\implies \mathsf {Area = 9 \times 2 = 18cm^{2}}

\implies \bf {Yes}

5 0
2 years ago
Read 2 more answers
) Picture frames are produced such that the four sides of a picture frame consist of two pieces from a population whose mean len
Natali [406]

Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

Perimeter of rectangle = 2(A + B)

Going by the illustration in the question, the perimeter is

==> 2(32 + 44) = 152 cm.

However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

Mean perimeter = (32 + 44)/2 = 38 cm.

Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars  =  44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

3 0
3 years ago
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