How do i solve and graph 3/4x + 8 < 41 on a number line

Mathematics

1 answer:

Tema [17]2 years ago

3 0

Answer:

get the inequality first ! x<44

Step-by-step explanation:

3/4x+8<41 ( subtract 8 from both sides. 8 cancels out. and 41-8=33 )

3/4x<33 ( multiply both sides by 4/3)

3/4 ×4/3 = 1

33×33 =44

x<44

and to graph it your line should have a open circle on 44 and point to the left.

kinda like this:

<—————○

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