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ivanzaharov [21]
2 years ago
12

How do i solve and graph 3/4x + 8 < 41 on a number line

Mathematics
1 answer:
Tema [17]2 years ago
3 0

Answer:

get the inequality first ! x<44

Step-by-step explanation:

3/4x+8<41 ( subtract 8 from both sides. 8 cancels out. and 41-8=33 )

3/4x<33 ( multiply both sides by 4/3)

3/4 ×4/3 = 1

33×33 =44

x<44

and to graph it your line should have a open circle on 44 and point to the left.

kinda like this:

<—————○

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irakobra [83]
35 is the answer of right please heart or comment
3 0
3 years ago
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The table shows the data of a random sample of fish that were collected from and later released into a lake.
yan [13]
280 eels

92 + 56 + 52 = 200
eel = 56/200

 56    *5       x   
-----    =   --------
200   *5   1000
56(5) = 280 x = 280

56/200 = 7/25 
7/25 = 280/1000
6 0
3 years ago
Damario invite friends over for a special dinner. For drinks, he made 32 gallons of lemonade. Each gallon had 16 cups. Each of D
Katen [24]
The answer is 382 and it’s correct
8 0
3 years ago
PLZZZZZZZZZZ HELP
MrRissso [65]
<h2>Answer:</h2>

The correct answer is:   Option: A

A.   85, 78, 80, 108, 46, 66, 68, 82, 72, 68

<h2>Step-by-step explanation:</h2>

It is given that:

The whisker ranges from 66 to 85.

The box ranges from 68 to 82 with the vertical bar inside the box at 75.

  • Hence, the minimum value of the box plot is: 66
  • Maximum value of box plot is: 85

Also,

  • The first quartile or the lower quartile i.e. Q_1 is: 68
  • The middle quartile or median i.e. Q_2 is: 75
  • The upper quartile or third quartile i.e. Q_3 is: 82

Also, it is given that:

One dot mark above forty-six.

One dot mark above one hundred and eight.

A)

On arranging the data in increasing order after removing outliers 46 and 108 we have:

 66    68    68    72    78    80    82     85  

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=75\\\\\\Q_3=81

As all the values matches the value defined.

Hence, this option is correct.

B)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    70   70   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=70\\\\\\Q_3=81

As the value of Q_2=70\neq 75.

Hence, this option is incorrect.

C)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    72    78   80   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=70\\\\Q_2=79\\\\\\Q_3=81

As the value of  Q_1,Q_2\ and Q_3 do not match.

Hence, this option is incorrect.

D)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    72   78   80    80     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=79\\\\\\Q_3=80

As the value of  Q_3=80\neq 82 do not match.

Hence, this option is incorrect.

4 0
3 years ago
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Rewrite 2/20 : 1/40 as a unit rate
Valentin [98]

Answer:

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Step-by-step explanation:

<u>Given:</u>

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(i) Change the ratio sign to division (÷). i.e

2/20 ÷ 1/40

(ii) Solve the expression by changing the division to multiplication(×). This also means you will need to swap the numerator and the denominator of the second term. i.e (1 / 40) becomes (40 / 1)

(2/20) × (40 / 1) = \frac{2}{20} × \frac{40}{1} = \frac{4}{1}

B). Now convert the result from above to unit rate. A unit rate is a rate in which the denominator has a value of 1.

So to convert   \frac{4}{1}  to unit rate, we keep simplifying until the denominator becomes 1.

And since the denominator is already 1, there is no need for further simplification.

Therefore, 2/20 : 1/40 to unit rate is  \frac{4}{1}

5 0
3 years ago
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