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Ludmilka [50]
2 years ago
6

What’s the volume of a cylinder with a radius of 6ft and height of 14ft? pls show work

Mathematics
1 answer:
Daniel [21]2 years ago
5 0

Answer:

<em><u>Given </u></em><em><u>-</u></em>

  • <em><u>radius </u></em><em><u>of </u></em><em><u>cylinder </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u> </u></em><em><u>ft</u></em>
  • <em><u>height </u></em><em><u>of </u></em><em><u>cylinder </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em><em><u> </u></em><em><u>ft</u></em>

Now ,

volume = \pi \: r {}^{2} h \\  =  >  \frac{22}{\cancel{7}}  \times 6 \times\cancel{ 14} \\  \\  =  > 22 \times 6 \times 2 \\  =  > 264 \: ft {}^{3}

hope helpful~

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Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

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(x,y)

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