All categories

3 years ago

If one side of a square measures (3x-8) find the area of the square

Mathematics

2 answers:

UkoKoshka [18]3 years ago

8 0

Answer:

9x^2 - 48x + 64

Step-by-step explanation:

Step 1: FOIL

(3x - 8)(3x - 8)

3x * 3x = 9x^2 First

3x * - 8 = -24x Outside

- 8 * 3x = -24x Inside

- 8 * - 8 = 64 Last

Step 2: Combine

9x^2 - 24x - 24x +64

Step 3: Simplify

9x^2 - 48x + 64 (Answer)

Wittaler [7]3 years ago

7 0

Answer:−21x−8

Step-by-step explanation: All sides have the same measure in a square, therefore all sides are 3x-8. Area is equal to 3x-8 times 3x-8 which is −21x−8

You might be interested in

Which square root is a rational number ? Square root 50, square root 70, square root 81, square root 96

Elis [28]

Answer:

square root of 81

Step-by-step explanation:

$\sqrt{81} = 9$

so 9 is rational number.

the rest are irrational number

8 0

3 years ago

10.Mr. Vickers earns a 7.5% commission on his total sales. Last month, he had sales of

Leno4ka [110]

Answer:

4096.50, 4,096.50, $4,096.50, or $4096.5

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

[(3•2+5)2]2-4 12356789

Gelneren [198K]

Answer:

−49427112 us the correct answer

8 0

2 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

3 years ago

This math problem makes me wanna kym

jek_recluse [69]

Answer:

-5-1/4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers