Question:
Solve the equation 2x2−5x+3=0 by the method of completing square.
Answer:
We have,
2x2−5x+3=0
⇒x2−25x+23=0 (Dividing throughough by 2)
⇒x2−25x=−23 (Shifting the constant term on RHS)
⇒x2−2(45)x+(45)2=(45)2−23 (Adding (21Coeff.ofx)2 onboth sides)
⇒(x−45)2=1625−23⇒(x−45)2=16
Assuming you already have your slope. Let’s assume you have a slope of 3/4. (m=3/4)
Slope intercept form is y=mx+b
y and x being a point
m is your slope
and b is your y-intercept
So for example, you have a y-intercept of 3, your equation would be y=3/4x+3
Standard form is Ax+By=C
answer choice a
x^2 - 5x - 1 = 0
a=1, b=-5, and c=-1
next you plug in the numbers into the quadratic formula
-(-5) plus or minus the square root of (-5)^2 - 4(1)(-1)/ 2(1)
after you simply, you should get 5 plus or minus the square root of 29, which is answer choice a
Answer:
b
Step-by-step explanation:
8×19= 152
1 : 4.5
152×4.5=684
Answer:
3 boys may be answer of this question
