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Liono4ka [1.6K]
2 years ago
5

An above-ground swimming pool is leaking. The function h(d) = 48 - 1. 5d gives the height of the water in the pool in inches d d

ays after the leak began.
Part A: Evaluate h(0). Show your work. What does this value represent in the problem?
Part B: Evaluate h(5). Show your work. What does this value represent in the problem?
Part C: Write and solve an equation to determine how long it will take the pool to empty if the leak is not repaired. Explain how you set up your equation.
Part D.
Based on your answers above, should the domain for this function be restricted? If not, explain why not. If so, explain why and give the restricted domain. !!!!! Please help don’t give fake answers!!!!
Mathematics
1 answer:
MAXImum [283]2 years ago
5 0

Answer:

A) 48 in : initial height of the water

B) 40.5 in : height of the water after 5 days

C) 32 days

D) Yes, should be restricted.

Domain: 0 ≤ d ≤ 32

Step-by-step explanation:

h(d) = 48 - 1. 5d

A)  

h(0) = 48 - 1. 5(0)=48

48 in is the initial height of the water

B)

h(5) = 48 - 1. 5(5)=48-7.5=40.5

40.5 in is the height of the water after 5 days

C) when the pool is empty, h = 0.

So set the equation to zero and solve for d.

\implies 48 - 1. 5d=0\\\\\implies 1.5d=48\\\\\implies d=\dfrac{48}{1.5}\\\\\implies d=32

D) Yes, the domain should be restricted because when d > 32, h < 0 and the height of the water in the pool cannot be negative

Domain: 0 ≤ d ≤ 32

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Find f(-5) and f(12) for each piecewise function f(x){-4x+3 if x&lt;3
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<h3>Answers:</h3>
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  • f(12) = 433

==================================================

Explanation:

The given piecewise function is

f(x) = \begin{cases}-4x+3 \ \text{ if } \ x < 3\\-x^3 \ \text{ if } \ 3 \le x \le 8\\3x^2+1 \ \text{ if } \ x > 8\end{cases}

At first piecewise functions may be strange confusing things, but they aren't so bad. I like to think of it like this: f(x) is a function that changes its identity based on what the input x is. We have three situations

  • f(x) = -4x+3 when x < 3
  • f(x) = -x^3 when 3 \le x \le 8
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In a sense, we have three different functions but they are combined somehow.

If x is smaller than 3, then we go for the first definition. Or if x is between 3 and 8, then we go for the second definition. Or if x is larger than 8, then we go for the third definition.

-----------------------

f(-5) means f(x) when x = -5. We see that -5 is smaller than 3, so x = -5 makes x < 3 true. We'll use the first definition

f(x) = -4x+3

f(-5) = -4(-5)+3

f(-5) = 20+3

f(-5) = 23

------------------------

Now the input is x = 12. This is larger than 8. In other words, x = 12 makes x > 8 true. We'll use the third definition

f(x) = 3x^2+1

f(12) = 3(12)^2+1

f(12) = 3(144)+1

f(12) = 432+1

f(12) = 433

------------------------

Side notes:

  • We won't use the second definition since we don't have any x inputs between 3 and 8
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