Answer:
- 0.26
- 0.91
- 1.43
Step-by-step explanation:
given data
mean = 1.9 hours
standard deviation = 0.3 hours
solution
we get here first random movie between 1.8 and 2.0 hours
so here
P(1.8 < z < 2 )
z = (1.8 - 1.9) ÷ 0.3
z = -0.33
and
z = (2.0 - 1.9) ÷ 0.3
z = 0.33
z = 0.6293
so
P(-0.333 < z < 0.333 )
= 0.26
so random movie is between 1.8 and 2.0 hours long is 0.26
and
A movie is longer than 2.3 hours.
P(x > 2.3)
P( 
> 
)
P (z > 
)
P (z > 1.333 )
= 0.091
so chance a movie is longer than 2.3 hours is 0.091
and
length of movie that is shorter than 94% of the movies is
P(x > a ) = 0.94
P(x < a ) = 0.06
so
P( 
< 
)
a = 1.43
so length of the movie that is shorter than 94% of the movies about 1.4 hours.
Answer:
B: {(3,1), (7,9)}
Step-by-step explanation:
For equation 2x-y=5, we can isolate y, so it's easier to solve later:
y = 2x - 5
y = (x - 4)^2
Now, notice that both equations are equal to y, so we can set them equal to each other:
(x-4)^2 = 2x-5
x^2-8x+16 = 2x - 5
x^2-10x+21=0
Now, we can factorize by finding 2 numbers that multiply to 21 and add up to -10:
(x-3)(x-7)=0
x=3 or x=7
Since B is the only one with the x values of 3 and 7, the answer must be B.
But to further check our answer, we can plug x back to any of the equations above to check for y:
(3-4)^2 = 1
(7-4)^2 = 9
Therefore, we can confirm that the answer is B.
4x (4 peaches) = 4y (4.96$)
x (4/4 peaches=1) = y (4.96$ / 4 = 1.24$)
y f(x) = 1.24$
A net is basically a flattened out 3D solid. If you fold all the sides up, you would end up with the 3D model.
Answer:
The height of the big cone is double the one in the small cone
h2 = 2h1
Step-by-step explanation:
Given that:
- The volume of the small cone: 5 cubic inches
- The volume of the big cone: 10 cubic inches
As we know, the volume of a cone is as following:
V = (1/3)*area of the base*height
If the base diameter are unchanged => area of the base of the two cones are unchanged and from the given information, the volume of the big cone is double the volume of the small cone. So the height of the big cone is double the one in the small cone
<=> h2 = 2h1
