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2 years ago

What's the highest common factor of 5y and y^2?

Mathematics

2 answers:

dangina [55]2 years ago

4 0

Hello.

The highest common factor of

$\mathrm{5y} \:and\:y^{2}$

$y$

y is the greatest common factor (G.C.F.) also called the Highest Common Factor (HCF)

Therefore, y is the highest common factor of 5y and y².

I hope it helps.

Have a nice day.

$\boxed{imperturbability}$

lys-0071 [83]2 years ago

3 0

<h3>Answer: y</h3>

This is because y is a factor of 5y and it's also a factor of y^2 = y*y

It's the largest common factor between the two given expressions.

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The median household incomes in dollars in four towns over time are shown. Assume the median incomes increase linearly. Median H

marysya [2.9K]

Answer:

Step-by-step explanation:

Household. Year 2010. Year 2015. Difference

Adderley. 47,200 58,200. 11,000

Bonniville. 52,900. 62,400. 9,500

Clay City. 44,600. 57,600. 13,000

Daletown. 41,500. 54,000. 12,500

Percentage increase for Adderley = 11,000/47,200 * 100= 23.3%

Percentage increase for Bonniville = 9,500/52,900 * 100= 17.96%

Percentage increase for Clay City = 13,000/44,600 * 100= 29.15%

Percentage increase for Daletown = 12,500/41,500 * 100= 30.12%

We can now see that Bonniville is the city with the lowest rate of increase in median household income.

7 0

3 years ago

Ella is a landscape photographer. One weekend at her art gallery she sells a total of 52 prints for a total of $2,975. How many

abruzzese [7]

Answer:

Ella sold the each print for the cost of $57.21.

Step-by-step explanation:

The total number of prints sold at gallery = 52

Total amount it is sold for = $2,975

Noe, If 52 prints are sold for $2,975.

⇒ $\textrm{Cost of 1 print} = \frac{\textrm{Total cost of 52 prints}}{\textrm{52}}$

$= \frac{2,975}{52} = 57.21$

or, Cost of 1 print = $57.21

So, Ella sold the each print for the cost of $57.21.

4 0

3 years ago

What is the least common multiple of 3 and 9

Tju [1.3M]

LCM(3, 9) = 9

because 9 = 3 × 3

5 0

3 years ago

Read 2 more answers

Three consecutive integers have a sum of 42. find the integers.

ioda

The answer is 13,14,15.

6 0

3 years ago

A group of 86 people consist of men women and children. There are twice as many women then there are men. There are 6 more child

weqwewe [10]

Answer: 16 men

32 women

38 children

Step-by-step explanation:

Let x represent the number of men in the group.

Let y represent the number if women in the group.

Let z represent the number of children in the group.

A group of 86 people consist of men women and children. This means that

x + y + z = 86 - - - - - - - - - - - - 1

There are twice as many women than there are men. It means that

x = y/2

There are 6 more children than there are women. This means that

z = y + 6

Substituting x = y/2 and z = y + 6 into equation 1, it becomes

y/2 + y + y + 6 = 86

multiplying through by 2, it becomes

y + 2y + 2y + 12 = 172

5y = 172 - 12 = 160

y = 160/5 = 32

x = y/2 = 32/2

x = 16

z = y + 6 = 32 + 6

z = 38

8 0

3 years ago