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2 years ago

What's the highest common factor of 5y and y^2?

Mathematics

2 answers:

dangina [55]2 years ago

4 0

Hello.

The highest common factor of

$\mathrm{5y} \:and\:y^{2}$

$y$

y is the greatest common factor (G.C.F.) also called the Highest Common Factor (HCF)

Therefore, y is the highest common factor of 5y and y².

I hope it helps.

Have a nice day.

$\boxed{imperturbability}$

lys-0071 [83]2 years ago

3 0

<h3>Answer: y</h3>

This is because y is a factor of 5y and it's also a factor of y^2 = y*y

It's the largest common factor between the two given expressions.

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3 years ago

Which expression is equivalent to 6a + 15? A. 6(a + 5) B. 3(2a + 5) C. 3(3a + 12) D. 6(a + 12) PLEASE HELP :)

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4 years ago

Read 2 more answers

) The manager of a local Gap store estimates that on average the probability of a customer entering the store and will purchase

xeze [42]

Answer: 1. 0.0256

2. 0.4096

Step-by-step explanation:

Binomial probability formula , to find the probability of getting x successes:

$P(x)=^nC_xp^x(1-p)^{n-x}$ , where n= Total number of trials

p= Probability of getting success in each trial.

Let x be the number of customers will make purchase.

As per given , we have

p= 0.20

n= 4

1. The probability that 3 of the next 4 customers will make a purchase will be:-

$P(x=3)=^4C_3(0.20)^3(1-0.20)^{4-3}$

$P(x=3)=(4)(0.20)^3(0.80)^{1}\ \ [\because\ ^nC_{n-1}=n]$

$P(x=3)=(4)(0.008)(0.80)=0.0256$

Hence, the probability that 3 of the next 4 customers will make a purchase = 0.0256

2. The probability that none of the next 4 customers will make a purchase will be :

$P(x=0)=^4C_0(0.20)^0(1-0.20)^{4-0}$

$P(x=0)=(1)(0.80)^{4}\ \ [\because\ ^nC_{0}=1]$

$P(x=0)=0.4096$

Hence, the probability that none of the next 4 customers will make a purchase= 0.4096

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3 years ago

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4 years ago

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sergeinik [125]

Answer:

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