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3 years ago

ℎ()=―4+ 5, find the value of ℎ(–3)

Mathematics

1 answer:

frez [133]3 years ago

4 0

Answer:

Step-by-step explanation:

Suppose that f(2) = −4, g(2) = 3, f '(2) = −5, and g'(2) = 1.

Find h'(2).

(a) h(x) = 4f(x) − 5g(x)

Use the constant multiple and difference rules:

h'(x) = 4f '(x) − 5g'(x)

h'(2) = 4*f'(2) − 5*g'(2), now substitute values and solve

h'(2) = 4*(−5) − 5*1 = −20 − 5 = −25

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How many significant figures are in each of these problems -2000+20.5 -106.2+54.07

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Answer:

3 significant figures

Step-by-step explanation:

Problems given:

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3 years ago

Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).

Vesnalui [34]

Answer:

Point D: $(0,-4, 1 )$

d = √41

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Pre-Calculus

Midpoint Formula [3D]: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )$
Distance Formula [3D]: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Step-by-step explanation:

Step 1: Define

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

Step 2: Find Point D

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )$
Add/Subtract: $(\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )$
Divide: $(0,-4, 1 )$

Step 3: Find distance d

Simply plug in the 2 coordinates A and D into the distance formula to find distance d

Substitute [DF]: $d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}$
Subtract/Add: $d = \sqrt{(-1)^2+(-6)^2+(2)^2}$
Exponents: $d = \sqrt{1+36+4}$
Add: $d = \sqrt{41}$

5 0

3 years ago

Assume that the average life of a refrigerator is 14 years, with the standard deviation given in part (a) before it breaks. Supp

fiasKO [112]

Answer:

The guarantee should be made of $X = 1.555 + 14\sigma$ years, in which $\sigma$ is the standard deviation given in part (a).

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Assume that the average life of a refrigerator is 14 years

This means that $\mu = 14$

The standard deviation given in part (a) before it breaks.

This will be the value of $\sigma$

However, the company does not want to replace more than 6% of the refrigerators under guarantee. For how long should the guarantee be made?

We need to find the 100 - 6 = 94th percentile, which is X when Z has a pvalue of 0.94. So X when Z = 1.555. So

$Z = \frac{X - \mu}{\sigma}$

$1.555 = \frac{X - 14}{\sigma}$

$X = 1.555 + 14\sigma$

The guarantee should be made of $X = 1.555 + 14\sigma$ years, in which $\sigma$ is the standard deviation given in part (a).

7 0

3 years ago

ℎ()=―4+ 5, find the value of ℎ(–3)​

ℎ()=―4+ 5, find the value of ℎ(–3)