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3 years ago

For which value of theta is sintheta= -1?pi/2pi3pi/22pi

Mathematics

1 answer:

zmey [24]3 years ago

7 0

Answer:

3π/2

Step-by-step explanation:

It may help you to realize that the (x, y) coordinates of the point on the unit circle are ...

(x, y) = (cos(θ), sin(θ))

Since you want sin(θ) = -1, look for the point on the unit circle that has a y-value of -1. It is the point (0, -1) at the bottom of the circle, where the angle is shown as ...

θ = 3π/2

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Can anyone help me find the (?,?) coordinates? The given shape is a parallelogram.

Sonja [21]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Given shape is a parallelogram.

Construction: Draw a line joining the diagonals.

<em>In parallelogram, diagonals bisect each other.</em>

Solve it using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

Using this midpoint find the missing coordinate.

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinates and y-coordinates.

$$ \frac{m+h}{2}=\frac{x}{2}, \ \ \ \frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x, n = y

x = m + h and y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

7 0

3 years ago

For which value of theta is sintheta= -1?pi/2pi3pi/22pi​

For which value of theta is sintheta= -1?pi/2pi3pi/22pi