Answer:
Two and hundredths
Step-by-step explanation: I'm in college so I think I am capable of answering a middle school question thank you very much, and make sure to mar me brainliest.
The first term of the arithmetic progression exists at 10 and the common difference is 2.
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How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8
5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
brainly.com/question/1486233
#SPJ4
Answer:
There are 70 sheep in the farm.
Step-by-step explanation:
Consider the provided information.
Let c represents the cows, s represents the sheep and p represents the pigs.
The number of cows and the number of sheep are in the ratio 6:5.


The number of sheep and the number of pigs are in the ratio 2:1.


The total number is 189.

Substitute the value of c and p in above.




Hence, there are 70 sheep in the farm.
Answer:
$460
Step-by-step explanation:
let the number of melons be x
4x + 3x + 3x = 200 melons
10x = 200 so, x will be 20
4x = 80 melons
3x = 60
3x = 60
amount made by 1st child = 80 × $2 = 160$
the remaining melons are 60 + 60 = 120
amount collected: they sold them in groups of 2 and each group was $5. so,
120÷2 × $5 = $300
total amount = 300 + 160 = $460.