6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
In order to find the unit rate
in ft / sec of 300 yards / min.
We first have to elicit the conversion
values for each unit of measurement, this will allows us identify how much will
we multiply in order to get the goaled value.
Conversion values:
<span><span>1.
</span>1 yard = 3
feet</span>
<span><span>2.
</span>1 minute =
60 seconds</span>
Solution:
<span><span>
1.
</span>300 yards x
3 feet/1 yard = 900 feet</span>
<span><span>2.
</span>1 minute x
60 seconds / 1 minute = 60 seconds</span>
Thus, 900ft/60sec
Grayson's mistake was that he multiplied 4 and 3 and then used the exponent he had to square 3 and then multiply it by 4.
Emily's mistake was that she added 2 to 36 instead of multiplying it by -2
Pat's mistake was that he forget to make y into -2 instead of 2
The right way to do this is 4(3^2)+2(-2)
(3^2)=9 9×4=36 2(-2)=-4 -4+9=5
