All categories

2 years ago

Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999

Mathematics

1 answer:

sp2606 [1]2 years ago

7 0

Answer:

1 999 000

Step-by-step explanation:

Formula:

$1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right) }{2}$

………………………………………

Then

$1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right) }{2}$

$1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right) }{2}$

$1+2+3+....+1997+1998+1999=\frac{3998000 }{2}$

$1+2+3+....+1997+1998+1999=1999000$

You might be interested in

Henry invested $4,300 in an account paying an interest rate of 3.6% compounded quarterly. Assuming no deposits or withdrawals ar

lana66690 [7]

Answer:

12.67 years

Step-by-step explanation:

5 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago

An Item , Which Is Regularly $4.60 , Is On Sale For One-Fourth Off. What Is The Sale Price?

vova2212 [387]

1/4 = .25
4.60 x .25 = 1.15
4.60 - 1.15 = 3.45

3.45$ is your answer.

5 0

3 years ago

You go for a half day hike. In 44 hours, you hike 10

nataly862011 [7]

44 divided by 10 will give you the answer

6 0

3 years ago

Read 2 more answers

When a curve and a line meet at a point, are their gradient equal?

Natali [406]

Check the picture below.

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

well, by the definition of a derivative, the slope at the point is f'(a), and any tangent line going through it will also have the same exact slope, keeping in mind that a straight line has a constant slope.

4 0

3 years ago