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victus00 [196]
2 years ago
13

Compute 1 + 2 + 3 +....+ 1,997 + 1,998 + 1,999

Mathematics
1 answer:
sp2606 [1]2 years ago
7 0

Answer:

1 999 000

Step-by-step explanation:

Formula:

1+2+3+.\ .\ .+n=\frac{n\times \left( n+1\right)  }{2}

………………………………………

Then

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 1999+1\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{1999\times \left( 2000\right)  }{2}

1+2+3+....+1997+1998+1999=\frac{3998000  }{2}

1+2+3+....+1997+1998+1999=1999000

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Brainliest to who answers first!
alexdok [17]

Answer:

correct answers

15 m=1,500

117 mm=0.117 m

79 m=0.079 km

hope it helps

5 0
3 years ago
The height of two similar pails are 12cm and 8cm.The larger pail can hold 2litres. What is the capacity of the smaller pail?
Vedmedyk [2.9K]

Answer:

1.33 liters

Step-by-step explanation:

Volume of any shape is given by cross sectional area multiplied by height. Therefore, V=Ah

Where A is area and h is height

Since their cross sections are the same, then volume depends on height.

If 12cm equals 2 liters

8cm equals x

X=(2*8)/12=1.3333333333333 liters

Approximayely, the smaller pail has capacity of 1.33 liters

7 0
3 years ago
HELP IM SO SORRY IJAGEHQKSHAQHGSVWHSBWBSNSJWBSBEJEJEJEJJEEJ JUST HELP. JUST HELP ME OGMFBSBSBGSGSBSBANSJSJSJS NUMBERS 13 and 14!
xxMikexx [17]
14.The answer is 10 Celsius
4 0
3 years ago
A gambler has a fair coin and a two-headed coin in his pocket. He selects one of the coins at random. (a) When he flips the coin
Aleks04 [339]

Answer:

a) probability of choosing heads= 1/2 (50%)

b)  probability of choosing the fair coin knowing that it showed heads is= 1/3 (33.33%)

Step-by-step explanation:

Since the unfair coin can have 2 heads or 2 tails , and assuming both are equally possible . then

probability of choosing the fair coin  (named A)= 1/2

probability of choosing an unfair coin with 2 heads (named B)= (1-1/2)*1/2= 1/4

probability of choosing an unfair coin with 2 tails (named C)= (1-1/2)*(1-1/2)= 1/4

then

probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B + probability of choosing C * probability of getting heads from C =

1/2*1/2 + 1/4*1 + 1/4*0 = 2/4 = 1/2

the probability of choosing the fair coin knowing that it showed heads is

P(A/B) = P(A∩B)/P(B)

denoting event A= the coin is fair and event B= the result is heads

P(A∩B) = 1/2*1/2 = 1/4

but since we know now that that the unfair coin is not possible , the probability of choosing heads is altered:

P(B)=probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B  = 1/2*1/2+1/2*1 = 3/4

then

P(A/B) = P(A∩B)/P(B)  = (1/4)/(3/4) = 1/3

then the probability is 1/3

8 0
3 years ago
Pls explain super confused <br> Thx
eimsori [14]
3+2•6/3
first you multiply the 2 and 6 on the top to get 12
so now it’s
3+12/3
now add the 12 and 3
15/3
now divide
so your answer is 5
7 0
3 years ago
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