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maks197457 [2]
2 years ago
7

Need help with math problem give 5 stars and brain thingy point

Mathematics
1 answer:
rewona [7]2 years ago
4 0

Answer:

b) 2/6

Step-by-step explanation:

0, 1/6, 2/6, 3/6, 4/6, 5/6, 1

Hope this helps!

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A pair of pants with a marked price of $35.00 has a discount of 20%. How much is the discount? Can someone help me learn to do p
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When you see a "%" you need to ask " a percent of what"?

Here, it's a percent of the original prize, so the discount is 20% of the original prize, that is 20% of 35.

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\frac{1}{5} *35=7

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Phoenix [80]

Answer:

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Step-by-step explanation:

Im also a girl teehee

3 0
3 years ago
Evaluate 3x +2y - 4z/x for x =5, y=-2,z=10
Evgen [1.6K]

3x + 2y - 4z/x for x=5, y=-2, z=10

3x + 2y - 4z/x

3(5) + 2(-2) - 4(10)/(5)

15 - 4 - 40/5

15 - 4 - 8

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3 0
3 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
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