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3 years ago

PLEASE HELP ILL GIVE BRAINLIEST

Mathematics

2 answers:

slega [8]3 years ago

8 0

Answer:

A rectangular prism is a 3D figure with 6 rectangular faces. To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units. Created by Sal Khan.

Step-by-step explanation:

pls give me brainliest

mr Goodwill [35]3 years ago

7 0

Answer:

It is 6!! im doing the same test can you help me out with my question?

Step-by-step explanation:

You might be interested in

What is the value of m in the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="\frac{1}

Novosadov [1.4K]

Answer:

The value of m is 44

Step-by-step explanation:

We have given:

1/2 m - 3/4 n = 16

Put the value of n in the given equation

1/2m - 3/4(8)=16

Now 4 and 8 will be canceled out by the table of 4

1/2 m - 3(2)=16

1/2m - 6 = 16

Now take the L.C.M of the denominator and solve for numerator:

m-2(6)/2 = 16

m-12/2 = 16

m-12 = 16*2

m-12 = 32

Add 12 at both sides:

m-12+12 = 32+12

m= 32+12

m=44

The value of m is 44....

6 0

3 years ago

Read 2 more answers

These are Questions/answers for #1, 2, 3, 17, 18, 19 & 20 if you can't see what it says in the picture (Please answer all qu

kkurt [141]

Answer:

See below for answers and explanations (along with a graph for #3)

Step-by-step explanation:

Problem #1

Applying scalar multiplication, $-4w=-4\langle-96,-180\rangle=\langle384,720\rangle$ .

Its magnitude would be $||-4w||=\sqrt{384^2+720^2}=816$ .

Its direction would be $\displaystyle\theta=tan^{-1}\biggr(\frac{720}{384}\biggr)\approx61.927^\circ\approx62^\circ$ .

Thus, B) 816; 62° is the correct answer

Problem #2

Find the time it takes for the ball to cover 13ft:

$x=(24\cos48^\circ)t\\13=(24\cos48^\circ)t\\t\approx0.8095$

Find the height of the ball at the time it takes for the ball to cover 13ft:

$y=6.1+(24\sin48^\circ)t-16t^2\\y=6.1+(24\sin48^\circ)(0.8095)-16(0.8095)^2\\y\approx10.053$

Thus, A) 10.053 is the correct answer

Problem #3

We have $u=\langle0,-8\rangle$ and $v=\langle6,0\rangle$ as our vectors. Thus, $u+v=\langle0+6,-8+0\rangle=\langle6,-8\rangle$ . Attached below is the correct graph. You can also solve the problem visually by using the parallelogram method where the resultant vector is the diagonal of the parallelogram.

Problem 4 (#7)

$\displaystyle t \cdot v=(7)(-10)+(-3)(-8)=-70+24=-46$

Thus, C) -46 is the correct answer

Problem 5 (#8)

Find $r$ and $\theta$ :

$r=\sqrt{x^2+y^2}=\sqrt{2^2+(-8)^2}=\sqrt{4+64}=\sqrt{68}=2\sqrt{17}\approx8.246$

$\displaystyle\theta=tan^{-1}\biggr(\frac{y}{x}\biggr)=tan^{-1}\biggr(\frac{-8}{2}\biggr)\approx-75.964^\circ$

Find the true direction angle accounting for Quadrant IV:

$\theta=360^\circ-75.964^\circ=284.036^\circ$

Write the complex number in polar/trigonometric form:

$z=8.246(\cos284.036^\circ+i\sin284.036^\circ)$

Thus, C) 8.246(cos 284.036° + i sin 284.036°) is the correct answer

Problem 6 (#12)

Eliminate the parameter and find the rectangular equation:

$x=3t\\\frac{x}{3}=t\\ \\y=t^2+5\\y=(\frac{x}{3})^2+5\\y=\frac{x^2}{9}+5\\9y=x^2+45\\0=x^2-9y+45\\x^2-9y+45=0$

Thus, D) x^2-9y+45=0 is the correct answer

Problem 7 (#13)

Find the magnitude of the vector:

$||v||=\sqrt{(-77)^2+36^2}=85$

Find the true direction of the vector accounting for Quadrant II:

$\displaystyle \theta=tan^{-1}\biggr(\frac{36}{-77}\biggr)\approx-25^\circ=180^\circ-25^\circ=155^\circ$

Write the vector in trigonometric form:

$w=85\cos155^\circ i+85\sin155^\circ j$

Thus, D) w=85cos155°i+85sin155°j is the corrwect answer

Problem 8 (#15)

$\frac{z_1+z_2}{2}=\frac{(3-7i)+(-9-19i)}{2}=\frac{-6-26i}{2}=-3-13i=(-3,-13)$

Thus, C) (-3,-13) is the correct answer

Problem 9 (#16)

Treat the golf ball and wind as vectors:

$u=\langle1.3\cos140^\circ,1.3\sin140^\circ\rangle$ <-- Golf Ball

$v=\langle1.2\cos50^\circ,1.2\sin50^\circ\rangle$ <-- Wind

Add the vectors:

$u+v=\langle1.3\cos140^\circ+1.2\cos50^\circ,1.3\sin140^\circ+1.2\sin50^\circ\rangle\approx\langle-0.225,1.755\rangle$

Find the magnitude of the resultant vector:

$||u+v||=\sqrt{(-0.225)^2+1.755^2}\approx1.769$

Find the true direction of the resultant vector accounting for Quadrant II:

$\displaystyle \theta=\tan^{-1}\biggr(\frac{1.755}{-0.225}\biggr)\approx-82.694^\circ\approx-83^\circ=180^\circ-83^\circ=97^\circ$

Thus, B) 1.769 m/s; 97° is the correct answer

Problem 10 (#17)

Identify the vectors and add them:

$u+v+w=\langle50\cos20^\circ,50\sin20^\circ\rangle+\langle13\cos90^\circ,13\sin90^\circ\rangle+\langle35\cos280^\circ,35\sin280^\circ\rangle=\langle50\cos20^\circ+13\cos90^\circ+35\cos280^\circ,50\sin20^\circ+13\sin90^\circ+35\sin280^\circ\rangle=\langle53.062,-4.367\rangle$

Find the magnitude of the resultant vector:

$||u+v+w||=\sqrt{53.062^2+(-4.367)^2}\approx53.241$

Find the true direction of the resultant vector accounting for Quadrant IV:

$\displaystyle \theta=\tan^{-1}\biggr(\frac{-4.367}{53.062}\biggr)\approx-4.705^\circ\approx-5^\circ=360^\circ-5^\circ=355^\circ$

Thus, A) 53.241, 355° is the correct answer

Problem 11 (#18)

We observe that $z_1=-8-6i$ and $z_2=4-4i$ , hence, $z_1+z_2=(-8-6i)+(4-4i)=-4-10i$

Thus, Q is the correct answer

Problem 12 (#19)

Find the dot product of the vectors:

$F_1\cdot F_2=(12000*14500)+(7000*-5000)=174000000+(-35000000)=139000000$

Find the magnitude of each vector:

$||F_1||=\sqrt{12000^2+7000^2}=1000\sqrt{193}\\||F_2||=\sqrt{14500^2+(-5000)^2}=500\sqrt{941}$

Find the angle between the two vectors:

$\displaystyle \theta=\cos^{-1}\biggr(\frac{F_1\cdot F_2}{||F_1||||F_2||}\biggr)\\ \theta=\cos^{-1}\biggr(\frac{139000000}{(1000\sqrt{193})(500\sqrt{941})}\biggr)\\\theta\approx49.282^\circ\approx49^\circ$

Thus, C) 49° is the correct answer

Problem 13 (#20)

Using scalar multiplication, $7v-2w=7\langle8,-3\rangle-2\langle-12,4\rangle=\langle56,-21\rangle-\langle-24,8\rangle=\langle56-(-24),-21-8\rangle=\langle80,-29\rangle=80i-29j$

Thus, A) -80i - 29j is the correct answer

6 0

2 years ago

A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time t

sergiy2304 [10]

Answer:

0.3 to 2.3 min

Step-by-step explanation:

n1=n2=10

x1=48

x2=49

s1=4

s2=1

Determine the deegres of freedom.

$\delta=\frac{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2})^2}{\frac{(\frac{s_1^2}{n1})^2}{n_1-1}+\frac{(\frac{s_1^2}{n1})^2}{n_2-1}}=10.14$

t=2.037 (student's appendix)

$E=t\sgrt(\frac{s_1^2}{n_1}+\frac{s^2_2}{n_2})=1.3$

$(x_1-x_2)-E=(48-49)-1.3=-2.3$

$(x_1-x_2)+E=(48-49)+1.3=0.3$

We are 95% confident that average commuting time for rute A is between 0.3 and 2.3 min shorter than for rute B.

5 0

4 years ago

There are orange, yellow and blue sweets in a box. The ratio of the

DanielleElmas [232]

Answer:

25%

Step-by-step explanation:

Sum the parts of the ratio, 7 + 5 + 4 = 16 parts

Of the 16 parts, 4 parts are blue, thus percentage is

$\frac{4}{16}$ × 100% = $\frac{1}{4}$ × 100% = 25%

7 0

3 years ago

The table shows values for functions f(x) and g(x) .

sladkih [1.3K]

The first thing we must do for this case is to equal both functions and clear the value of x. Thus, we obtain the values that satisfy both equations.
However, there is another solution route. We have a table with the values.
The solution for f (x) = g (x) will be all x satisfying both equations simultaneously.
f (0) = g (0) = 1
f (1) = g (1) = 1/2
answer
x = 0
x = 1
Note:
F (0) in the table is incorrect if the function is
f (x) = 0.5x
F (0) in the table is correct if the function is
f (x) = 0.5 ^ x

5 0

3 years ago