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2 years ago

5

Please help ^^^^^^^^ a= 4, 7, 15? b= 7, 15, 4? c= 15, 4, 7?

1 answer:

zysi [14]2 years ago

3 0

Answer:

A is 15, B is 1, and c is 4!

Step-by-step explanation:

This is because 15 (rooted number) would be the main focus, and since the x (normally by the rooted number) doesn't have a label (like 2x, 3x, etc.) it will be one. Then, the 4 (last number) is c (since it is on the outside and is likely the divisor.

Good luck!

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2 years ago

Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1

jek_recluse [69]

Answer:

$S_{31}=71.3$

Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

$U_n=a_1+(n-1)d$

We were given that the 9th term is $17$ .

$\Rightarrow 17=a_1+(9-1)(-2.1)$

$\Rightarrow 17=a_1+(8)\times(-2.1)$

$\Rightarrow 17=a_1-\frac{84}{5}$

$\Rightarrow 17+\frac{84}{5}=a_1$

$\Rightarrow a_1=\frac{169}{5}$

The sum of the first n-terms is given by the formula,

$S_n=\frac{n}{2}(2a_1+(n-1)d)$

To find $S_{31}$ , we substitute $n=31$ , $a_1=\frac{169}{5}$ and $d=-2.1$ .

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})$

$\Rightarrow S_{31}=\frac{713}{10}$

$\Rightarrow S_{31}=71.3$

The correct answer is D

8 0

3 years ago

Read 2 more answers

Can someone please help me on 12

mixer [17]

Well first, you need to solve within the parentheses. You would get 23.8 - 14 - 8.6

Then you would subtract them in order, and your answer would be 1.2

6 0

2 years ago

7x-4y=-7 5x+y=22 please show work

Keith_Richards [23]

What exactly are you finding

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2 years ago