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GarryVolchara [31]
3 years ago
6

Graph y=-6(3)^x please do the table and the graph 20 POINTS!

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

<em>Explanation to the answer below... (Answers in the Explanation</em><em>)</em>

Step-by-step explanation:

We Know that our rule is y = y = -6(3)^{x} , which means we can use this rule to find y from x. Since we don't know what X, is, we have to assume numbers like 1, to 7. And there is no space to write on the graph, I'll put a virtual copy of a graph.

1st Point,

y = -6(3)^{x}\\y =  -6(3)^{1}\\y = -6(3)\\y = -18\\x = 1, y = -18

2nd, point

y = -6(3)^x\\ y = -6(3)^2\\y = -6(9)\\y = -54\\x = 2, y = -54

3rd Point

y = -6(3)^x\\y = -6(3)^3\\y = -6(27)\\y = -162\\x = 3, y = -162

4th Point

y = -6(3)^4\\y = -6(81)\\y = -486\\x = 4, y = -486\\

5th Point

y = -6(3)^5\\y = -6(243)\\y = -1458\\\x = 5, y = -1458

6th Point

y = -6(3)^x\\y = -6(3)^6\\y = -6(729)\\y = -4,374\\x = 6, y = -4,374\\

7th Point (Last Point)

y = -6(3)^x\\y = -6(3)^7\\y = -6(2,187)\\y. = -13,122\\x = 7, y = -13,122

Let's now plot them on the Graph, the values are so big, the graph might look a little odd.

Always remember that we can continue the points infinitely, and there is no stop, The Graph is attached below...

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From the given table, we have that the lateral limits of f(x) as x -> 3 are different, hence the limit of f(x) does not exist at x = 3.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value. For the limit to exist, the lateral limits have to be the same, as follows:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x)

In this problem, we have that:

  • To the left of x = 3, that is, for values that are less than x = 3, f(x) - > -3.
  • To the right of x = 3, that is, for values that are greater than x = 3, f(x) -> 4.

Hence the lateral limits are given as follows:

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Since the lateral limits are different, the limit does not exist.

More can be learned about lateral limits at brainly.com/question/26270080

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