What is 1/5 × -3/2 +4/5 × -2/7 × -1/6 × -2/7

Mathematics

2 answers:

velikii [3]3 years ago

4 0

Answer:

$\frac{-457}{1470}$

Step-by-step explanation:

$\frac{1}{5} \times \frac{-3}{2} + \frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7}$

$(\frac{1}{5} \times \frac{-3}{2}) + (\frac{4}{5} \times \frac{-2}{7} \times \frac{-1}{6} \times \frac{-2}{7})$

$\frac{-3}{10} +\frac{-16}{1470}$

$=\frac{-457}{1470}$

netineya [11]3 years ago

4 0

Answer: 4/1225

Step-by-step explanation:

1/5 × -3/2 +4/5 × -2/7 × -1/6 × -2/7

Multiplying an even number of negative terms makes the product positive:

= 1/5 * 4/5 * 1/7 * 1/2 * 1/7

= 1/5 * 4/5 * 1/7 * 1/7

= 4/1225

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What are the domain and range of the function?<br> f(x) = ^3 square x - 3

DerKrebs [107]

Step-by-step explanation:

$f(x) = \sqrt[3]{x - 3}$

The domain of a function are the values of $x$ that you can plug into the function $f(x)$ .

Values inside of a root must be non-negative, which means that $x - 3$ must be greater than or equal to zero. We can set up an equation to find the domain:

$x - 3 \geq 0$

$x \geq 3$

With this, we know the domain of the function is $[3, \inf)$ .

The range of a function are the values that $f(x)$ can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is $[0, \inf)$ .