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4 years ago

Find the area of a regular hexagon with a 48- inch perimeter

1 answer:

7 0

First, you must find the side length. It is a hexagon so there are 6 sides. You take the perimeter by 6 48/6 and get 8. Then plug it into formula (3 sqrt 3)/2 a^2 where a is side length. Plug into formula and get an answer of 166.28 in^2

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Evaluate 1/4 c + 3d when c = 6 and d = 7

Naddika [18.5K]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Replace c with 6, and d with 7:-

$\Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}$

$\bigstar$ On simplification,

$\Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4} +21$}$

$\bigstar$ On further simplification,

$\Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}$

$\bigstar$ Adding the numerators,

$\Large\text{$\displaystyle\frac{90}{4}$}$

$\bigstar$ Finally, Reducing the fraction:-

$\Large\text{$\displaystyle\frac{45}{2}$}$

$\Uparrow$ $\mathbb{OUR\:SIMPLIFIED\:EXPRESSION}$

<h3>Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

8 0

2 years ago

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May someone help me plz!!!!!!!!!!!!ASAP!!!!!!!!!!!!!!!!!

katovenus [111]

(a) x = 0.36--, 100x = 36.36--, 100x-x = 36, x = 36/99 = 4/11
(b) x = 0.36-, 100x = 36.6-, 100x-x = 36.3, x= 363/990=11/30
(c) 36/100 = 9/25

8 0

3 years ago

PLEASE HELP ASAP! Will give brainliest to best answer!

oksian1 [2.3K]

Answer:

Step-by-step explanation:

It looks like it would be c=4b but 4*7 equals 28 not 30

4 0

3 years ago

Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equ

astraxan [27]

Answer:

The Point in the first quadrant is $(\sqrt[2]{2.0268} ,6.559)$ .

Step-by-step explanation:

Since

we know the general equation of the circle whose center is at (h,k) and radius is r that is

$(x-h)^2+(y-k)^2 =r^2$

we have given center is (0,3) and radius is r= 4

substituting in the general equation of the circle we get

$x^2 +(y-3)^2 = 16$

Now substituting the y= 2.5x + 3 in the above equation we get

$x^2 +(2.5x + 3-3)^2 = 4^2$

$x^2 +6.25x^2 = 16$

here subtracting 16 from both sides and also perform addition

we get

$7.25x^2 = 16$

dividing both sides by 7.25 we get

$x^2 =2.2068$

taking square root both sides we get

$x= \frac{+}{-}\sqrt[2]{2.0268}$

but we need positive value of x because both x and y are positive in the first quadrant

that is

$x= \sqrt[2]{2.0268}$

substituting this into the given equation of the line we get

y = 2.5( $\sqrt[2]{2.0268}$ )+3

y = 6.559

so the point in the first quadrant is ( $\sqrt[2]{2.0268}$ ,6.559)

that is required

6 0

4 years ago

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10 , 12 , 6 ,1 ,9 ,16 , 20, 17,8<br><br> Median ???

allochka39001 [22]

Answer:

its 10

Step-by-step explanation:

You have to put them from least to most and see the middle number.

5 0

3 years ago

Read 2 more answers