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mezya [45]
2 years ago
7

The volume of a barrel of oil is 257166 cm3 round this figure to the nearest hundred thousand

Mathematics
1 answer:
Fudgin [204]2 years ago
3 0

Answer: Hope this helps :D

the answer is 300000 cm3

Step-by-step explanation:

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What does A = and what does B =​
krek1111 [17]

Answer:

Step-by-step explanation:

<UWV = 180° - 50° - 50° ( SUM OF ANGLE IN A TRIANGLE)

<UWV = 80° which is angle A

b = 20 ( isosceles triangle)

8 0
3 years ago
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Formula of amount when interest and principal is given<br>​
NISA [10]

Answer:

We can rearrange the interest formula, I = PRT to calculate the principal amount. The new, rearranged formula would be P = I / (RT), which is principal amount equals interest divided by interest rate times the amount of time.

Step-by-step explanation:

Hope this helps you sorry if it does not help you

5 0
2 years ago
If u multiply 2/3 x 6/10, will the product be more than 6/10 or less than 6/10? How do you know?
Elanso [62]

Answer:

More

Step-by-step explanation:

You can find a common denominator and get 20/30 * 18/30 = 38/30, which is more than 18/30.

5 0
3 years ago
Consider the probability that greater than 26 out of 124 software users will call technical support. Assume the probability that
Mekhanik [1.2K]

Answer:

Since n(1-p) = 3.72 < 10, the normal curve cannot be used as an approximation to the binomial probability.

100% probability that greater than 26 out of 124 software users will call technical support.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

np \geq 10 and n(1-p) \geq 10

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Out of 124 software users

This means that n = 124

Assume the probability that a given software user will call technical support is 97%.

This means that p = 0.97

Conditions:

np = 124*0.97 = 120.28 \geq 10

n(1-p) = 124*0.03 = 3.72 < 10

Since n(1-p) = 3.72 < 10, the normal curve cannot be used as an approximation to the binomial probability.

Consider the probability that greater than 26 out of 124 software users will call technical support.

The lowest possible probability of those is 27, so, if it is 0, since it is considerably below the mean, 100% probability of being greater. We have that:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 27) = C_{124,27}.(0.97)^{27}.(0.03)^{97} = 0

1 - 0 = 1

100% probability that greater than 26 out of 124 software users will call technical support.

3 0
3 years ago
A -76x+76=-76x+76−76x+76=−76x+76minus, 76, x, plus, 76, equals, minus, 76, x, plus, 76 (Choice B) B 76x+76=-76x+7676x+76=−76x+76
Pie

Answer:

b

Step-by-step explanation:

i could be wrong

5 0
3 years ago
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