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3 years ago

Use the diagram to complete the statements.

Mathematics

2 answers:

prisoha [69]3 years ago

4 0

Answer: 3, 4, Point R to Point Q, and depression from Point Q to Point R

Step-by-step explanation: just took it

andrey2020 [161]3 years ago

3 0

Answer:

3, 4, Point R to Point Q, and depression from Point Q to Point R

Step-by-step explanation:

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Find the area of the triangle

Bess [88]

Answer:

b x h / 2

Step-by-step explanation:

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3 years ago

Read 2 more answers

True or false: 3^-1 x 3^-1=3^1

Tresset [83]

Answer:

the answer I got is false

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2 years ago

Kyra has a rock collection. When she puts her rocks into 2 equal plies, there are no rocks left over. When she puts her rocks in

Nat2105 [25]

Step-by-step explanation:

According to this description we need a number that can be divided by 2,3 and 4 since the amount of rocks can be described by a natural number. However if a number is divided by 4 it is divided by 2 as well since 2*2=4.

$\frac{x}{4} = \alpha \\ \frac{x}{2} = 2 \alpha$

If α is a natural number then 2*α is a natural number as well as the product of two natural numbers.

Which means that we need a number devided by 3 and 4.

The smallest number that fulfills this demand is 3*4=12.

Also any product of 12 with any natural number can be devided by 3, 4 and 2.

If the exercise asks for the numbers that are divided only by 2,3 and 4 these are:

${3}^{ \alpha } \times 12 \: and \: {4}^{ \alpha } \times 12 \: \\ where \: \alpha \: belongs \: to \: the \: set \: of \: all \: \\ natural \: numbers$

8 0

3 years ago

janet 's gross pay is $750 from which $31 is deducted for OASDI $10 for medicare , and $14 for an income tax. What is her net pa

myrzilka [38]

Her net pay would be $695. You subtract $31, $10 and $14 from $750, and that is what she would take home.

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3 years ago

Find the values of m and b that make the following function differentiable. the piecewise function f of x equals x cubed when x

aalyn [17]

$f(x)=\begin{cases}x^3&\text{for }x\le1\\mx+b&\text{for }x>1\end{cases}$

$f$ must be continuous in order to be differentiable, so we need to have

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$

By its definition, $f(1)=1^3=1$ , and

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}x^3=1$

$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}(mx+b)=m+b$

so that $\boxed{m+b=1}$ .

We want the derivative to exist at $x=1$ , which requires that we pick an appropriate value for $f'(1)$ so that $f'(x)$ is also continuous. At the moment, we know