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Drupady [299]
3 years ago
6

Given that a­­^b = x, evaluate the following:2a^3b +a^2b +a^b

Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

  2x^3 + x^2 + x

Step-by-step explanation:

For ...

a^{b}=x

The expression ...

2a^{3b}+a^{2b}+a^{b}

can be rewritten as ...

2(a^{b})^3+(a^b)^2+(a^b)=2x^3+x^2+x

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3 years ago
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The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

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The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

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3 years ago
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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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