Answer: don't know sorry
Step-by-step explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET !!!!!!!!!!!!!!!!!!!!!!!!
Have a nice day Bye! :)
we can use synthetic division
and then we can find quotient
we can see in the image
we will get
![quotient=2x+7](https://tex.z-dn.net/?f=%20quotient%3D2x%2B7%20)
![remainder=0](https://tex.z-dn.net/?f=%20remainder%3D0%20)
![(2x^2+9x+7)=(x+1)(2x+7)](https://tex.z-dn.net/?f=%20%282x%5E2%2B9x%2B7%29%3D%28x%2B1%29%282x%2B7%29%20)
so, we get
.............Answer
Answer:
7.5 m 457.5
![m^{2}](https://tex.z-dn.net/?f=m%5E%7B2%7D)
Step-by-step explanation:
First, visualize the original cone and the smaller cone as overlapping similar triangles. The scale factor of the original cone to the smaller cone is 50:40, so if the smaller cone has a radius of 6 m, then the radius of the original cone would be 7.5 m.
The volume of the frustum is the volume of the original cone minus the volume of the smaller cone. The formula for the volume of a cone is V =
.
Original Cone =
=
= 937.5![\pi](https://tex.z-dn.net/?f=%5Cpi)
Smaller Cone =
=
= 480![\pi](https://tex.z-dn.net/?f=%5Cpi)
Frustum = 937.5
- 480
= 457.5![\pi](https://tex.z-dn.net/?f=%5Cpi)
Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector =
square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
![A = \frac{1}{2} r^2 \theta](https://tex.z-dn.net/?f=%20A%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20r%5E2%20%5Ctheta%20)
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
![A = \frac{\pi}{2}](https://tex.z-dn.net/?f=%20A%20%3D%20%5Cfrac%7B%5Cpi%7D%7B2%7D)
The area of the sector =
square units