ACDF is a trapezoid and
1 answer:
Answer:
x = 7
Step-by-step explanation:
See the attached figure.
As shown: A C D F is a trapezoid and BE is a mid-segment.
The mid-segment of the trapezoid is the average of its bases.
BE = 0.5 ( A F + C D)
Given: CD = 18 , BE = 2x + 10 and A F = 6x - 12
So,
2x + 10 = 0.5 ( 18 + 6x - 12)
Solve for x
2x + 10 = 0.5 (6 + 6x)
2x + 10 = 3 + 3x
10 - 3 = 3x - 2x
∴ x = 7
<u>So, the value of x is 7</u>
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Answer:
The absolute value can be graphed using the points around the vertex (-2, 0), (-4, 2), (-3, 1), (-1, 1), (0, 2).
Step-by-step explanation:
The find the x coordinate of the vertex, set the inside of the absolute value x + 2 equal to 0. In this case, x + 2 = 0.
x + 2 = 0
Subtract 2 from both sides of the equation.
x = -2
Replace the variable x with -2 in the expression.
y = |(-2) + 2|
The absolute value vertex is (-2, 0).
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
For each x value, there is on y value. Select few z values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.
Substitute the x value -4 into f(x) = |x+2|. In this case, the point is (-4,2).
y=2
Substitute the x value -3 into f(x) = |x+2|. In this case, the point is (-3,1).
y=1
Substitute the x value 0 into f(x) = |x+2|. In this case, the point is (0,2).
y=2
You can find the graph in the attachment.
