Perimeter of triangle = all sides added up
3a + 4 + 2a - 7 + 9a + 11
now add like terms
3a + 2a + 9a = 5a + 9a = 14a
4 - 7 + 11
= -3 + 11 = 8
so we have 14a + 8
as our simplest expression
A. c <= -4 so is the top graph;
b. c > 4 so is the second graph;
c. c < 10 so will be a graph with an open circle starting at 10 and going left towards negative infinity
It was 210 cm.
The function she used is h(t) = 210 + 33t. This is a linear function, since it is of the form f(x) = mx+b. In a linear function, we have the slope, m, which tells us how much the height increases per year, and the y-intercept, b, which tells us how tall it was when we began measuring. Our m value would be 33 and our b would be 210, so the original height was 210.
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.