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olga2289 [7]
3 years ago
8

A pyramid with a square base of length 3cm and height 16cm

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
H = 16 cm
s = 16.0702 cm
a = 3 cm
e = 16.14 cm
r = 1.5 cm
V = 48 cm3
L = 96.421 cm2
B = 9 cm2
A = 105.421 cm<span>2

The volume of a square pyramid:V = (1/3)a2hSlant Height of a square pyramid:By the Pythagorean theorem, we know thats2 = r2 + h2since r = a/2s2 = (1/4)a2 + h2, ands = √(h2 + (1/4)a2)This is also the height of a triangle sideLateral Surface Area of a square pyramid (4 isosceles triangles):For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a, and for this calculation our height for the triangle is slant height s.  With four
 sides we need to multiply by 4.L = 4 x (1/2)as = 2as = 2a√(h2 + (1/4)a2)Squaring the 2 to get it back inside the radical,L = a√(a2 + 4h2)Base Surface Area of a square pyramid (square):B = a2Total Surface Area of a square pyramid:A = L + B = a2 + a√(a2 + 4h2))A = a(a + √(a2 + 4h2))</span>
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Height of the cone having volume as 25.12 \text { cm}^{3} and base area 12.56 \text { cm}^{2} is 6 cm.

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Given that volume of cone = 25.12 \text{ cm}^{3}

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