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olga2289 [7]
3 years ago
8

A pyramid with a square base of length 3cm and height 16cm

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
H = 16 cm
s = 16.0702 cm
a = 3 cm
e = 16.14 cm
r = 1.5 cm
V = 48 cm3
L = 96.421 cm2
B = 9 cm2
A = 105.421 cm<span>2

The volume of a square pyramid:V = (1/3)a2hSlant Height of a square pyramid:By the Pythagorean theorem, we know thats2 = r2 + h2since r = a/2s2 = (1/4)a2 + h2, ands = √(h2 + (1/4)a2)This is also the height of a triangle sideLateral Surface Area of a square pyramid (4 isosceles triangles):For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a, and for this calculation our height for the triangle is slant height s.  With four
 sides we need to multiply by 4.L = 4 x (1/2)as = 2as = 2a√(h2 + (1/4)a2)Squaring the 2 to get it back inside the radical,L = a√(a2 + 4h2)Base Surface Area of a square pyramid (square):B = a2Total Surface Area of a square pyramid:A = L + B = a2 + a√(a2 + 4h2))A = a(a + √(a2 + 4h2))</span>
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3a + 2a + 9a = 5a + 9a = 14a

4 - 7 + 11
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6 0
3 years ago
Match the inequality to the graph of its solution.
MrRissso [65]
A. c <= -4 so is the top graph;
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3 0
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Ever since renata moved to her new home, she's been keeping track of the height of the tree outside her window. h(t)h(t)h, left
lilavasa [31]
It was 210 cm.

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4 0
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Read 2 more answers
I need help ASAP please
Anna007 [38]
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7 0
2 years ago
The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde
Elenna [48]
Assume that
 a and b = the two legs of the right triangle. 
 c =  the hypotenuse.

The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500               (1)

The perimeter is 150yd, therefore
a + b + c = 150         (2)

Let the side fenced with wood be a, at $5/yd.  Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
 5a + 10b + 10c = 1200            
or
a + 2b + 2c = 240         (3)

From (2), obtain 
c = 150 - a - b              (4)

Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60

From (1), obtain
60b = 1500
b = 25

From (4), obtain
c = 150 - 60 - 25 = 65

Answer:
A. The length of the leg fenced with wood is 60 yd.
B.  The length of the leg fenced with steel is 25 yd.


5 0
3 years ago
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