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djverab [1.8K]
3 years ago
11

How do i do this forming lons ​

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
I’m not sure, but when I don’t understand something I watch a video. Try watching a video about it.
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2 902 991.17 grams in 3.2 tons

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Please help I will give out brainliest
Nitella [24]

Answer:

i)x=0,x=1

ii)

\frac{2}3} + \frac{\sqrt{40} }{6}  \\\frac{2}3}-\frac{\sqrt{40} }{6}

Step-by-step explanation:

so I did not use the graphs actually.

for the answer to question i), i wrote out the equation as given:

3x^2-3x+2=2

then, i subtracted the two from the right side of the equation to make the equation set equal to 0, and I got:

3x^2-3x+2-2=+2-2, which becomes 3x^2-3x=0

then, I used the quadratic method of taking out the greatest common factor, which in this case is 3x, and the equation becomes:

3x(x-1)=0

finally, for this equation, I set 3x=0 and x-1 =0 to get the solutions to this equation, as shown below

3x=0(divide both sides by 3 to get)x=0

x-1=0(add 1 to both sides to get)x=1

now for the second equation, I had no other choice but to use the quadratic formula to find the solutions.

so I set up the quadratic formula as shown:

\frac{-(-4)+ or -\sqrt{(9-4)^2)-4(-2)(3)} }{2(3)}

from there the equation gets simplified down to:

\frac{4+ or -\sqrt{16-4(-6)} }{6}

simplifying the formula even further gives us:

\frac{4+ or -\sqrt{40} }{6}

if we simplify the equation one last time, we get:

\frac{2}{3} + or -\frac{\sqrt{40} }{6}

therefore, the solutions to this equation are:

\frac{2}{3} +\frac{\sqrt{40} }{6}\\ \frac{2}{3} - \frac{\sqrt{40} }{6}

8 0
3 years ago
True ot false? K = 3 over 5 is a solution to the inequality 15k + 3 < 15.
AysviL [449]
True, 15k and 3 is the same and greater than
5 0
3 years ago
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