this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
This problem is accompanied by a figure.
You can infere these relationships from the figure
(x-5)° = 74° => x = 74 + 5 = 79°
(x-5)° + 58° + (y-1)° = 180 ° => 74 + 58 + y-1 = 180 =>
y = 180 + 1 - 58 - 74 = 47°
Answer: x = 79°, y = 47°. This is the option d)
Answer:
n = 8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
6n + 7 = 55
<u>Step 2: Solve for </u><em><u>n</u></em>
- Subtract 7 on both sides: 6n = 48
- Divide 6 on both sides: n = 8
<u>Step 3: Check</u>
<em>Plug in n into the original equation to verify it's a solution.</em>
- Substitute in <em>n</em>: 6(8) + 7 = 55
- Multiply: 48 + 7 = 55
- Add: 55 = 55
Here we see that 55 does indeed equal 55.
∴ n = 8 is a solution of the equation.
Answer:
x= -12
Step-by-step explanation:
∠2= (180°-36°)÷2 (base ∠s of isos. △)
∠2= 72°
m∠2= x +84
72= x +84
x= 72 -84
x= -12
