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2 years ago

Write an equation based on the graph. Please help 15 points!

Mathematics

2 answers:

Alika [10]2 years ago

8 0

Answer:

The equation is y = - 3x - 3

Step-by-step explanation:

Step 1:

Equations always start with y = (unless you are in grade 11) in which case you start with f(x) =

Step 2:

Use rise over run to find the slope (since its based on graph, if not there is a formula to find it when given coordinate points only)

So to use rise over run, you count how many squares upwards starting from a point that aligns in the graph (in this case the bolded dots)

So you start at (-2, 3) and count how many squares up or down to the next bolded dot (if its up its positive, if you have to go down then its negative).

Then once youve reached the same y-value as the the other dot, count how many squares to the right.

So in this case, you have to go down 6 times and right 2 times.

So as a fraction its -6/2 but that can be simplified to just -3

So thats the slope: -3

Step 3

then you need to find the y-intercept (where the line touches the y-axis)

Its easy: you can visually see that the line crosses at -3.

and the format for the equation is y = mx + b

m = slope

b= y-intercept

SO: y= -3x - 3

Brainliest?

nignag [31]2 years ago

5 0

Answer should be:

y = -3x - 3

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Umnica [9.8K]

Answer:

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Step-by-step explanation:

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3 years ago

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For right triangle base and height can be legs.

We have one leg = 5 ft. (Lets think it is a base.)

We need to find the other leg.

We are going to use Pythagorean theorem.

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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3 years ago

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OLEGan [10]

Answer:

can you show the picture plz

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2 years ago