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Kryger [21]
3 years ago
6

A moose eats a lily pad. The food the moose eats is used to make ATP energy that can be used in cellular processes. The products

of photosynthesis are the reactants of cellular respiration. What is included in D in the diagram below? Choose ALL that apply.
Question 4 options:

This is multi answered

(A) water

(B) oxygen

(C) glucose

(D) sunlight

(E) carbon dioxide

Chemistry
1 answer:
AURORKA [14]3 years ago
6 0
Its is B (oxygen) and C (glucose)
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To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.
ZanzabumX [31]

To determine the mass of CO₂, the following must be known :

  • the molar mass of CaCO₃
  • the mole ratio of CaCO₃ to CO₂
  • the molar mass of CO₂
<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of  CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of  CaCO₃ from the molar mass of  CaCO₃

\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}

2. Find the mole ratio of  CaCO₃ : CO₂(from equation = 1 : 1)

\tt n_{CaCO_3}\div n_{CO_2}=1\div 1

3. Find the mass of CO₂ from the molar mass of CO₂

\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}

3 0
3 years ago
Read 2 more answers
How can I solve for this ? Calculate the mass of the precipitate formed when 2.27 L of 0.0820 M Ba(OH)2 are mixed with 3.06 L of
Maurinko [17]
The balanced chemical reaction is:

Na2SO4 + Ba(OH)2 = 2NaOH +BaSO4

We are given the amount of the reactants to be used. These values will be the starting point of our calculations.

0.0820 mol/L Ba(OH)2 (2.27 L solution) = 0.18614 mol Ba(OH)2
0.0664 mol/L Na2SO4 (3.06 L solution) = 0.20318 mol Na2SO4

The limiting reactant is the Ba(OH)2. The amount for this compound will be used.

0.18614 mol Ba(OH)2 (1 mol BaSO4 / 1 mol Ba(OH)2 ) (233.43 g BaSO4 / 1 mol BaSO4)= 43.4507 g BaSO4
7 0
3 years ago
Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

Explanation:

First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
Calculate the amount of moles equal to 50.0 g of barium<br> Please show your work
maw [93]
<h2>Answer:</h2>

We will use dimensional analysis to solve this.

We will need the molar mass of barium, which is 137.33 g/mol.

50g × \frac{1 mol}{137.33g} = .36 mol Ba

There are <em>.36 moles of barium</em> in 50g of barium

7 0
3 years ago
What is the mass number of 207Pb ? A: 289 B: 207 C: 125 D: 82
Sergio [31]
207 is the mass number. 82 would be the atomic number
3 0
3 years ago
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