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mixas84 [53]
3 years ago
10

Please Help! 30 Points! Please explain your answer.

Mathematics
1 answer:
deff fn [24]3 years ago
4 0
For this, you need to implement trigonometry, and the soa cah toa method is the one that I use. in this case you would use the tangent, which is toa, opposite over adjacent. in your calculator you will have to click the tan button on your calculator. in the parentheses type in 25 because that is the angle measure that you know. in this case, the side that you don't know is the adjacent side so it would be tan(25)=x/1 (I think it was a 1, it looked like the picture cut it off). this means to isolate the x you need to multiply it by the opposite length (the one on the bottom, 1) and so you need to multiply tan(25) by 1 (or whatever it is on the bottom of the equation/opposite length on the picture). you should get your answer that way and it should be bigger than the opposite side.
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The sum of two numbers is 40 - 13. what are the integers.
Anni [7]
So. let's say the numbers are "a" and "b"

whatever they're, we know a + b = 56

let's say the larger one is "b", so 3 times the smaller is 3*a or 3a
now, 12 less than that, is 3a - 12

and the larger is that, so b = 3a - 12

so   \bf \begin{cases}
a+b=56\\
\boxed{b}=3a-12\\
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a+\boxed{3a-12}=56
\end{cases}

solve for "a", to see what the smaller one is

what's b? well, b = 56 - a
6 0
3 years ago
Find the area of the shape shown below ​
Arlecino [84]

Answer: 12.5

Step-by-step explanation:

area= 1/2 (2.5+7.5) 2.5

sorry if its not clear enough i dont really know how else to explain it

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2 years ago
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I have no clue<br><br> Question 7
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5 0
2 years ago
A......B......C.......or D
IrinaVladis [17]
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5 0
3 years ago
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B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
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