Name three quaderlateral that only sometimes have right angle
Rhombus, trapezoid, and parallelogram
(3+3+3+3=12) (3x4=12)
(-3) +(-3)+ (-3)+ (-3)= (-12) (-3x4=-12)
Answer: I need da points
Step-by-step explanation: I’m just like that sry
Answer:
See attached picture.
Step-by-step explanation:
Graph the equation and test solutions to create a shaded region.
The original triangle had side lengths of 12. The perimeter was 36
Then if you divide each side by 4, each side would be 3 and the new triangle's perimeter would be 9. The difference of them would be 36-9 which is 27. The answer is 27. Hope that helped