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vlabodo [156]
2 years ago
15

4 - 2/8 = what is 4 minus a fraction of 2/8 equal to?

Mathematics
2 answers:
Sladkaya [172]2 years ago
8 0
4=32/8 so 32/8-2/8=30/8. 30/8 -> 15/4 or 3.75
Naddik [55]2 years ago
5 0

Answer:

= 15/4

Step-by-step explanation:

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You and your friend caught 36 sunfish in lake Okeechobee the number y of sunfish by your friend is 8 more than the number x caug
kotykmax [81]
8x+x=36
9×=36
x=4
why 20 characters
4 0
3 years ago
How are the shapes alike
Andrews [41]

Answer:

Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.

Step-by-step explanation:

3 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
The recommended angle for a firefighting ladder is 75°. When a 110-foot ladder
Licemer1 [7]

Answer:106.38 feet

Step-by-step explanation:

This can be solved by using pythagoras theorem

 

c=110 feet

b=28 feet

a=?

a=sqrt(110^2-28^2)

=sqrt(12100-784)

=sqrt(11316)

=106.3766 feet

=106.38

3 0
3 years ago
Find the indicated limit, if it exists.
Paha777 [63]
The limit is the y value that the graph approaches from both sides as x approaches the target limit

it they approach different values from the left and right sides, the limit does not exist

we want to find the limit as x approaches 5

we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5

evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0

f(5)=8

f(x)=x+3
f(5)=5+3
f(5)=8

it approaches 0 and 8 from both sides
the limit doesn't exist
D
8 0
3 years ago
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