Answer: 19.9
Step-by-step explanation: I got it off of delta math
We can define the speed as the quotient between the distance moved, and the time it takes to move that distance, so we have:
<u>speed = Distance/Time.</u>
Now we can rewrite this as:
<u>Distance = Speed*Time.</u>
We will find that the speed of the car was 21 mi/h.
Here the information given is:
Mr. Pipkins speed is: S = 3.5 mi/h
The car needed 27 "steps" to reach the corner.
Mr. Pipkins needed 27 + 135 = 162 "steps" to reach the same corner.
Because the number of steps is related to time and distance, the ratio between the number of steps should be the same as the ratio between the speeds:
162/27 = 6
(Pipkins needed 6 tomes more steps than the car, so the car moves 6 times faster than Pipkins)
This means that the speed of the car is 6 times larger than the speed of Mr. Pipkins.
Then the speed of the car is:
S' = 6*(3.5 mi/h) = 21 mi/h.
If you want to learn more, you can read:
brainly.com/question/24594539
Answer is A. Because it is located between 9 and 10
Answer:
4 t^2 + 6 t + 2
Step-by-step explanation:
h(t)=2t+1 and g(t)=2t+2
(g•h)(t) = (2t+1) (2t+2)
FOIL
first: 2t*2t = 4t^2
inner : 2t*1 =2t
outer: 2t*2 =4t
Last : 2*1 =2
Add them together
4 t^2 + 2 t+4t + 2
4 t^2 + 6 t + 2
