Answer:
100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.
Explanation:
In the given question it is mentioned that
S1=50%
V2=250ml
S2= 20%
We all know that
V1S1=V2S2
∴V1= V2×S2÷S1
∴V1= V2S2×1/S1
∴V1= 250×20÷50
∴V1= 100ml
Answer:
B
Explanation:
I think that the anserw is B.
the components of the pure substance will not be able to be separated by physical means
Answer:
I'm pretty sure the correct answer is b, I took this quite a while ago so I might not be right I would do some research about it. hope I helped!
