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liubo4ka [24]
3 years ago
14

Which two minerals make up the complex hydroxyapatite?

Chemistry
2 answers:
matrenka [14]3 years ago
6 0
Ca₁₀(PO₄)₆(OH)₂ - hydroxyapatite

b. phosphorus (P) and calcium (Ca)
lara [203]3 years ago
3 0
Phosphorus and calcium is the correct answer.
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You're at the zoo and have a big red 1.80 L helium balloon. The barometric pressure today is 785 mmHg. Then you hear the roar of
fomenos

Answer: The volume of the balloon up there is 6.192 L.

Explanation:

Given: V_{1} = 1.80 L,    P_{1} = 785 mm Hg (mm Hg = 0.00131579) = 1.032 atm

P_{2} = 0.300 atm,       V_{2} = ?

Formula used to calculate volume is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the value into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\1.032 atm \times 1.80 L = 0.300 atm \times V_{2}\\V_{2} = 6.192 L

Thus, we can conclude that the volume of the balloon up there is 6.192 L.

8 0
3 years ago
Can you help me out plz and thank u​
Nonamiya [84]

Answer:

stirring

Explanation:

when you stir it spreads the item out more to be fully covered and dissolve faster. like putting sugar in tea, if you don' t stir it wont dissolve  fast

5 0
3 years ago
What are Rhodium isotopes used for?
Lina20 [59]

Answer:

Rhodium is used to make electrical contacts, as jewelry and in catalytic converters, but is most frequently used as an alloying agent in other materials, such as platinum and palladium. These alloys are used to make such things as furnace coils, electrodes for aircraft spark plugs and laboratory crucibles.

Explanation:

4 0
3 years ago
Neon lamps, is composed of 90.483% of 20ne, 0.271% of 21ne, and 9.253% of 22ne. the 20ne atoms have a mass of 19.992 u, 21ne ato
WITCHER [35]

20.181 u

The average atomic mass of Ne is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,  

Avg. at. mass

= (0.904 83× 19.992 u) + (0.002 71 × 20.994) + (0.092 53× 21.991 u)

= 18.0894 u + 0.0569 u  + 2.0348 u = 20.181 u

8 0
3 years ago
When 1.008 g of hydrogen reacts with chlorine in a calorimeter containing 500.00 g water, the
jeyben [28]

The heat released by reaction : C) -8870 J

<h3>Further explanation</h3>

Given

1.008 g of hydrogen

500.00 g water

The temperature rises 25.00 °C to 29.24 °C

Required

energy required

Solution

Q absorbed by water :

Q = m.c.Δt

Q = 500 g x 4.18 J/g C x (29.24-25)

Q = 8870.08 J

The reaction to produce HCl is an exothermic reaction (releasing heat), so that Q is negative

Q water = -Q HCl = -8870.08 J

5 0
3 years ago
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