Answer:
See answer and picture below
Explanation:
In this case, the key to get an idea of how is the starting ether is with the final product and the empirical formula of the ether.
First, the empirical formula of the ether gives us information of the structure of the ether. This ether could be either an alkene, alkane or cycloalkane.
Alkane cannot be because alkane's formula is CnH(2n+2), so it's either an alkene or cycloalcane (CnH2n).
However, as we can see, it reacts with HI in excess, so, it cannot be an alkene because in this case the acid will react with the double bond of the ether too forming another product. This discart the fact that the ether has a double bond. So it has to be a cycloalkane.
As the innitial structure it's an ether, it should be either a cyclohexane or cyclopentane with a methyl group attached. So, how can we know which of these structures is? well, we can actually do the reaction with both reactants and see which match. In the attached picture you have the answer.
Hope this helps.
There is really no difference thermal energy and heat are pretty the same thing.
Answer:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The coefficient should be 3
Explanation:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The chemical equation is a reaction between ethanol and oxygen . The reaction yield is carbon dioxide and water. Balancing the chemical equation requires one to make the number of atoms on the reactant side be equal to the number of atoms on the product side.
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
The hydrogen atom on the left hand side of the equation is 6. Therefore, the number of atom of hydrogen should be 6 on the right hand side. The number of oxygen atom on the left hand side is 7. Therefore, the number of Oxygen atom on the right hand side should 7 . Oxygen atom in carbon dioxide(right hand side) is 4 atoms, therefore, it requires 3 atoms of oxygen to make the oxygen atoms 7.
Using 3 as the coefficient of water in the equation will make hydrogen 6 and oxygen 3 .Adding the 3 oxygen to the already 4 atoms of oxygen in carbon dioxide will make oxygen 7 atoms
The reaction is
Cu⁺²(aq) ---> Cu(s) [reduction]
The species which undergoes reduction is able to oxidize other one thus will called as "oxidizing agent"
Thus Cu⁺² is an oxidizing agent
or Cu is a reducing agent
Al(s) ---> Al⁺³(aq)
Aluminium is undergoing oxidation
Thus is able to reduced others and hence is a reducing agent
Al is a reducing agent
or Al⁺³ is an oxidizing agent
Answer: Cu is the reducing agent, and AI3+ is the oxidizing agent.