<u>Solution</u><u>:</u><u>-</u>
Let's find roots of x² - 3x + 2
=> x² - 3x + 2 = 0.
=> x² - x - 2x + 2 = 0.
=> x ( x - 1 ) -2 ( x - 1) = 0.
=> ( x - 1 ) ( x - 2 ) = 0.
=> x = 2, 1.
Now
- ( a + ß )² = (2+1)²=3²=9
- ( a - ß )² = ( 2 - 1 )² = 1² = 1.
So , equⁿ would be ,
=> x² - ( 9 + 1)x + 9×1=0.
<u>=> x² - 10x + 9=0.</u>
Answer:
D
Step-by-step explanation:
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
-1/2
Step-by-step explanation:
2(x-4)=6x-6
2x-8=6x-6
2x-6x-8=-6
-4x-8=-6
-4x=-6+8
-4x=2
x=2/-4
simplify
x=-1/2
Same as before, apples with apples: (A), girls both in the numerator, total both in the denominator, righty?
