Plz help I’m getting timed
Answer:
45
Step-by-step explanation:
9, 13, 17, 21, 25
We are adding 4 each time
9+4 = 13
13+4 =17
17+4 = 21
The common difference =4
a1 = 9
The formula is
an = a1+d(n-1) where n is the term number
an = 9+4(n-1)
We want the 10th term
a10 = 9+4(10-1)
= 9+4(9)
= 9+36
= 45
Hi,
So we have g(x) = 4√(x). We're looking for g(45). Think of it like this: whatever number is in the place of x in g(x), just place that number AS x.
Therefore, we have :
g(45) = 4√(45) ⇒ (4) × (√(45)) ⇒ (4)(3√(5)) = 12√(5).
-Hope this helps!