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Irina-Kira [14]
3 years ago
10

If h(x) =6 -x, what is the value of (h•h)(10)

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

Your exact value should be 10h^{2}

Step-by-step explanation:

I put it into the calculator and that's what came out.

Tju [1.3M]3 years ago
7 0

Answer:  16

Step-by-step explanation:

The given function : h(x) =6 -x

Then, the composition function of (h\cdot h)(x)=h(x)\times h(x)

\\\\\Rightarrow\ (h\cdot h)(x)=(6-x)(6-x)=(6-x)^2

Using identity (a-b)^2=a^2-2ab+b^2, we have

(6-x)^2=6^2-(2)(6)(x)+x^2\\\\\Rightarrow\ (h\cdot h)(x)=(6-x)^2=36-12x+x^2

Now, (h\cdot h)(10)=36-12(10)+(10)^2

=36-120+100=16

Hence, the value of (h\cdot h)(10)=16

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Triangle: solve for x
NARA [144]

Answer:

6 root two

Step-by-step explanation:

geometric mean for leg t.

24*3=x2

x2=72

x=root(72)

6 root two

if my answer helps please mark as brainliest.

6 0
3 years ago
Think I know this one but could do with some help
Andrei [34K]
Quick note: Since Riona wants to sell like 90 or 100 the answer I got was for 95.

I hope this helps you but the answer would be approximately about 83125.
7 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
3 years ago
What is the sum total of 2/3 + 5/10 =
sergey [27]
2•10+5•3
10•3
35/30*5 ( do it on both sides )
you'll get 7/6 or 1 1/6
8 0
3 years ago
-1/2 times -2/3 times -6/7=
fenix001 [56]

Answer:

Exact Form:  −2/7

Decimal Form: -0. 285714

8 0
3 years ago
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