How do you write a percent into a fraction or a mixed number in simplest form

Help me with this problem, please. I have more, but this is the first question.

riadik2000 [5.3K]

Answer: the answer to this question is 17

Step-by-step explanation:

4 0

3 years ago

Connor earns $ 2 3 dollar sign, 23 working every 1 .51 point, 5 hours. Complete the table to determine how many dollars Connor w

Aleks04 [339]

Pongase a estudiar aver que pex aver si mejor cara de pingaaa

4 0

3 years ago

What is 5x(23x2)<41 please i need the answer

pashok25 [27]

Answer:

x < 41/230

Step-by-step explanation:

5x x 46 < 41

230x < 41

4 0

3 years ago

The marketing manager for an automobile manufacturer is interested in determining the proportion of new compact-car owners who w

Serhud [2]

Answer:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

Step-by-step explanation:

Data given and notation

n=200 represent the random sample taken

X=79 represent the number of people that they would have purchased the GPS navigation system

$\hat p=\frac{79}{200}=0.395$ estimated proportion of people that they would have purchased the GPS navigation system

$p_o=0.3$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.3 or no.:

Null hypothesis: $p=0.3$

Alternative hypothesis: $p \neq 0.3$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

4 0

3 years ago

Guys please help with this question thanks

erastova [34]

= 16 + 49 - 3(11) - 4(10)
= 16 + 49 - 33 - 40
= -8

3 0

3 years ago