Aboslute value|10 blocks| + |3 blocks| + |-8 blocks| + |2 blocks| + |-7 blocks| + |4 blocks| + |-4 blocks| = ?

1 answer:

5 0

Absolute or modulus always gives a positive number.
For example, when I take absolute value of 4, I get
|4| = 4 and when I take absolute value of -4, I get |-4| = -(-4) = 4.

Therefore, no matter what the sign of quantity is, absolute or modulus will always make it positive.
Therefore,
|10 blocks| + |3 blocks| + |-8 blocks| + |2 blocks| + |-7 blocks| + |4 blocks| + |-4 blocks| = 10 + 3 -(-8) + 2 -(-7) + 4 -(-4) = 10+3+8+2+7+4+4 = 38

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2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c A= B= C= Please I'm gonna fail math

aleksley [76]

9514 1404 393

Answer:

a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

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You seem to have ...

$\dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)$

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Additional comment

I find it easy to remember the rules of exponents by remembering that an exponent signifies repeated multiplication. It tells you how many times the base is a factor in the product.

$2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}$