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Oxana [17]
3 years ago
7

Solve the system of equations: x - 3y = - 4 2x - 6y= 6

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

No Solution.

Step-by-step explanation:

x-3y=-4

2x-6y=6

-----------

simplify 2x-6y=6 into x-3y=3

-------------

x-3y=-4

x-3y=3

------------

x-3y=-4

-(x-3y)=-1(3)

-----------------

x-3y=-4

-x+3y=-3

---------------

0=-7

no solution

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A 32cm long string just fits round the perimeter of a square board. The area of the board is
Ierofanga [76]

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64cm2

Step-by-step explanation:

(32÷4)=8

8×8=64cm2

8 0
3 years ago
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Lin earned $50 last week. Andre earned 80% of what Lin earned. How much did Andre earn last week? *
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$40

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Turn the percentage into a decimal.

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3 years ago
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
Which of the following is a point-slope equation for a line with the point (-2, 4) and a slope of 3?
never [62]

Answer:

y=3x+10

Step-by-step explanation:

y-4=(x+2)3

y-4=3x+6

y =3x+10

5 0
3 years ago
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