Ask question

Ask question

All categories

3 years ago

10

Gabe bought 8 bananas at the market for $1.84. Lucy bought 6 bananas at the grocery store for $2.10 . One banana at the grocery

store is $ _______________ more than one banana at the market.

2 answers:

marissa [1.9K]3 years ago

8 0

35p

2.10 divided 6 =35p

Elina [12.6K]3 years ago

4 0

Answer:

one banana at the grocery store is 12 cents more than on banana at the market

You might be interested in

Which of the following could be its equation?

mrs_skeptik [129]

So to solve problems like these you can work out each equation by substituting the x and y with the coords from the vertex (2,-4) and which ever one is true is the corresponding equation.

Lets try the first one

A) y = 2( x-2)^2-4 this would become

-4 = 2(2-2)^2-4 we solve this and get

-4 = 2(0)-4

-4 = -4

so it seems like A is the correct answer, of course we'd wanna check out the other answers just to be sure.

Lets try one and do C

C) -2 = 2(-4-2)^2+2

-2 = 2(-8)^2+2

-2 = 130

These aren't equal so this can't be our equation

So you can also do one more just to be super sure you have the right answer but I think A is the correct one :)

5 0

3 years ago

Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

2 years ago

The circumference of F is 120 cm what is the length of DE the minor arc

AfilCa [17]

Answer:

Option E 15 cm

Step-by-step explanation:

we know that

The circumference of a circle subtends a central angle of 360 degrees

so

using proportion

Find out the length of arc DE by a central angle of 45 degrees

Let

x -----> the length of arc DE

$\frac{120}{360}=\frac{x}{45}\\\\x=120*45/360\\\\x=15\ cm$

7 0

3 years ago

A man paid $42.30 for gasoline in may, $38.60 in June, and $43 in July. What was the average monthly cost for gasoline?

jeyben [28]

The average is $41.30

3 0

3 years ago

Help me please will mark brainlyist

Leni [432]

Answer:

24.46

Step-by-step explanation:

4 0

3 years ago