Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
(1,4)
(4,1)
(2,3)
(3,2)
so there are 4 different combinations that equal 5
6 x 6 = 36 total possible outcomes of the dice
so they have a 4/36 reduces to 1/9 probability of equaling 5
Answer:
No
Step-by-step explanation:
To calculate the number of tiles needed
divide 4m by 0.2m for row of tiles ⇒ 20 tiles per row
divide 3m by 0.2m for column of tiles ⇒ 15 tiles per column
number of tiles = 20 × 15 = 300
number of packs = 300 ÷ 10 = 30
cost = 30 × £34.99 = £1049.70
Since she has £1000 to spend and £1049.70 > £1000
She does not have enough to cover the wall
