Answer:
x²-8x-1=0
comparing above equation with ax²+bx+c=0
a=1
b=-8
c=-1
x=
=(--8+-√(64-4×1×-1)/2×1
=8+-√(64+4)/2
taking positive
x=(8+√68)/2=2(4+√17)/2=4+√17
taking negative
x=(8-√68)/2=2(4-√17)/2=4-√17
maybe be it's right.....
(1,4)
(4,1)
(2,3)
(3,2)
so there are 4 different combinations that equal 5
6 x 6 = 36 total possible outcomes of the dice
so they have a 4/36 reduces to 1/9 probability of equaling 5
12
Step-by-step explanation:
Let's put the equations in standard form. For the first equation, we have:
−11y=6(z+1)-13y
2y−6z=6
y−3z=3
The second equation is:
4y−24=c(z−1)
4y−cz=24−c
If we multiply the first equation by 4, we get:
4y-12z=12
Comparing the two equations, we see that if c=12, both equations will be the same and there will be infinitely many solutions.
The correct value of c is 12.
(10,5), (-12,-6), (-18, -9), (-8, -4), (20,10)
(-15, 5), (-18, 6), (-21,7), (33, -11), (24, -8)
10/5=2, -12/-6=2, -18/-9=2, -8/-4=2, 20/10=2
-15/5= -3, -18/6= -3, -21/7= -3, 33/-11= -3, 24/-8= -3
but what we doo in this ur ques is half
