I think 1.00 mol sorry if I’m wrong
The number of electrons in an atom's outermost valence shell governs its bonding behaviour. Elements whose atoms have the same number of valence electrons are grouped together in the Periodic Table. ... Nonmetals tend to attract additional valence electrons to form either ionic or covalent bonds.
Answer:
Please find the explanation below
Explanation:
Traits are physically observed features of an organism. They are coded for and determined by genes, which comes in two forms called ALLELE. Each allele is responsible for a particular phenotype that makes up a trait. A dominant trait is the one which is expressed over another in a heterozygous state i.e. combined state of the two different alleles that encodes the two different traits respectively.
In this question, having horns is a recessive trait while being hornless is a dominant trait. The two traits are encoded by different alleles of the same gene. When the two different alleles combine in the organism's genotype, the dominant trait (hornless) will express itself over its contrasting trait (horn), hence, the animal will be phenotypically hornless. The allele that encodes hornlessness is said to be the dominant allele while hornlessness is the dominant trait.
Note that, in this dominance inheritance pattern, the recessive trait i.e. horned, will only phenotypically be expressed when the recessive allele is homozygous i.e. same in the organism's genotype.
<span><span>Number of Protons-19 </span><span>Number of Neutrons-20 </span><span>Number of Electrons-<span>19</span></span></span>
<h3>Answer:</h3>
Volume = 11.2 L
<h3>Explanation:</h3>
Step 1: Calculate Moles:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 3.01× 10²³ Particles ÷ 6.022 × 10²³
Number of Moles = 0.50 Moles
Step 2: Calculate Volume:
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.
When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,
= (22.4 dm³ × 0.50 moles) ÷ 1 mole
= 11.2 dm³ ∴ 1dm³ = 1 L
So,
Volume = 11.2 L
