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3 years ago

Why is cell division a necessary function of living things?

Chemistry

1 answer:

Nady [450]3 years ago

6 0

Because the older cells will not be able to function properly without the new cells taking over them. :)

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Write the electronic configuration of the Na +, Mg2 +, Ca2 + and Rb + ions. Research the size of these ions in picometers and or

Sunny_sXe [5.5K]

Answer:

pen

Explanation:

3 0

3 years ago

What is the wavelength of a wave having a frequency of 2.26 * 10 ^ 14 * s ^

liberstina [14]

ν = 2.26 * 10¹⁴ Hz

c = 3.0 * 10⁸

Using wave equation

c = λν

λ = c/ν

λ = 3.0 * 10⁸/2.26 * 10¹⁴

λ = 1.3 * 10⁻⁶

4 0

3 years ago

FILL IN THE BLANK! ILL GIVE BRAINLIEST The heat trapping nature of__and other gases was demonstrated in the mid 19th century

Gekata [30.6K]

<h2>Answer:</h2>

carbon dioxide

<h2>Explanation:</h2>

4 0

3 years ago

The number of atoms of sulfur in 2.66 grams of sulfur

Sedbober [7]

<h3>Answer:</h3>

5.0 × 10^21 atoms of sulfur

<h3>Explanation:</h3>

We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's number.

Therefore;

1 mole of an element = 6.022 × 10^23 atoms

Thus, 1 mole of sulfur = 6.022 × 10^23 atoms

But, molar mass of sulfur = 32.065 g/mol

This means;

32.065 g contain 6.022 × 10^23 atoms

Therefore, 2.66 g of Sulfur will contain;

= (2.66 g ÷ 32.065 g/mol) × 6.022 × 10^23 atoms

= 5.0 × 10^21 atoms

5 0

4 years ago

KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r

nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = $\Delta T=T_f-T_i$

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

$Q = mc\Delta T$

$Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)$

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= $\frac{10.1 g}{101 g/mol}=0.1 mol$

$KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)$

The heat of solution =

$\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol$

So, the equation correctly showing the heat of solution

$KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)$

4 0

4 years ago