Answer:
a)
And if we convert this interval into % we got (47.615%, 58.385%)
b) For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than most students at PCC own a car
Step-by-step explanation:
We can begin calculating the best estimator for the true proportion of students at PCC who own a car:
Part a
The confidence level is 95% , and the significance level would be given by and . And the critical values would be given by:
The confidence interval for the true proportion is given by the following formula:
Replacing the info given we got:
And if we convert this interval into % we got (47.615%, 58.385%)
Part b
For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than most students at PCC own a car
Equation 1) y = -3/2x + 9
Equation 2) 2x + 2y = 16
Add 3/2x to both sides of equation 1.
1) 3/2x + y = 9
Then, multiply all of equation one by 2.
1) 2(3/2x + y = 9)
1) 3x + 2y = 18
2) 2x + 2y = 16
Subtract.
x = 2
Plug in 2 for x in the first equation.
y=-3/2x+9
y = -3/2(2) + 9
y = -3 + 9
y = 6
So, x=2 and y = 6
~Hope I helped!~
I recommend to read whatever the person above said
The answer is:
32x^5+ 240x^4+ 720x^3+ 1080x^2+810x+243
I would say 24 considering your in middle school and maybe learning about rectangles or parallels